1hmmm okeyy ll post some more as soon ll get em
10 Answers
1wht does sereis limit of wavelength here means......is it the largest wavelength
49minimum is always 0 for a transition series...so series limit is maximum...[1]
1Q.If the radius of first bohr orbit is x ,then de broglie wavelength of electron in 3rd orbit is nearly::
a)2Ï€x b)6Ï€x
c)9x d)x/3
i did like this mvr =nh2Ï€
m*hmλr=nh2π
2πr=nλ
ie2πx=λ
λ2=3λ=6πx..........(b)
ma ans is comin out to be right but m not satisfied wid ma mehtod i think i ve mistaken somewhere..plzz help
49let the de broglie wavelength be λ1 and λ3 in 1st and 3rd orbits..
radius is a function of n2
so r3=9r1=9x
wavelength =2Ï€r/n=2*Ï€*9x/3=6Ï€x
now n=no of orbit...rthe quest may be why?
it is because the n value in nh/2Ï€ was considered to be the no of orbit by bohr
and this expression was proved by de broglie by taking n meaning to be the no of wavelengths in the respective orbits.
1if KE of a proton is increased to nine times , the wavelength of the de broglie wave associated wid it wud become
A)3 times B)9 timess
C)1/3 timess D)1/9 times
answer given is c
49mv=√2mE
λ=h/mv=h/√2mE
so λ becomes 1/3 times when E becomes 9 times..[1][1]