sir
as per your solution i am getting q=3*10-9
excess electrons =1.8*1010
total no. of atoms= 5*1022
so the answer i am getting is=3.7*10-13
and the correct answer given is 4.17*10-14
plz check my solution
Two carbon discs of 1.0 g each are 1.0 cm apart have equal and opposite charges. If forces of attraction between them is 1.0*10-5 N.
calculate the ratio of excess electrons to total atom on the negatively charged disc.
(permittivity constant is 9.0*109 Nm2c-2)
first find q
then divide by charge of electron to find the no of charged particles
then total no of atoms is given by no of moles of C x avogadro's number
no of moles is 1/12
I hope this out line helps
sir
as per your solution i am getting q=3*10-9
excess electrons =1.8*1010
total no. of atoms= 5*1022
so the answer i am getting is=3.7*10-13
and the correct answer given is 4.17*10-14
plz check my solution
Two carbon discs of 1.0 g each are 1.0 cm apart have equal and opposite charges. If forces of attraction between them is 1.0*10-5 N.
calculate the ratio of excess electrons to total atom on the negatively charged disc.
(permittivity constant is 9.0*109 Nm2c-2)
kQ2/r2= 10-5
kQ2/r2= 10-5
9.109Q2=10-5.10-4
Q2=10-18/9
Q=10-9/3
so your answer will get divided by 9 :)