C6H5COOH→(C6H5COOH)2
NOPW, VANT HOFF FACTOR i=1-α/2
ΔTf observed/ΔTfcalculated=1-α/2
now its just substituting in the formula
2g of C6H5COOH dissolved in 25g of benzene shows a depression in freezing point equal to 1.63k.Molar depression constant for benzere is 4.9K kg mol-1.what is the percentage association of acid if it forms double molecules in solutions?
C6H5COOH→(C6H5COOH)2
NOPW, VANT HOFF FACTOR i=1-α/2
ΔTf observed/ΔTfcalculated=1-α/2
now its just substituting in the formula