1dz2 is the answer .......... pls explain
The d-orbital participating in sp3d hybdn. is ???
Pls explain.....
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15 Answers
24see we have to see where min repulsion s theer..
since px,py,pz already there....so only valcant space in 3D is XY plane...
so it should be dxy
plzz confirm...
24how ???????????????along z there will be p orbital tooo
so how to accomodate dz2 orbtal too ?
39http://www.tutorvista.com/content/chemistry/chemistry-iv/atomic-structure/sp3d-hybridization.php
i guess that can help :P
1these are just the facts that one ought to know.......dz^2 is is the orbital with m=0 and hence it is the one involved........its just a fact and nothing to prove in here.....
3to be frank i will ask how come this fact.There must be reason,we may not know.sry arshad if i hurt u.
1357The reason may be this:
The bond length along the axial plane is larger than that on the equatorial plane.
So more is the d-contribution greater is the bond-length
So dz2 is good guess
24but sir more the bond length ,teh nbond will also be waeker naa ??
1d z2 is the answer..i remember the answer not the reason properly..i had asked dis one to mah teacher having seen the question in inorganic chem by OPTANDON.......
1i will try to ask again n let u ppl knw...but for dat wait 7 days..coz its puja time in Kolkata...:))