1Tushar please give full solution
1)Calculate the value of Avogadro constant from the internuclear distance of
adjacent ion in NaCl is 0.282 nm and the density of soild NaCl formula units is 2.17 × 103 kg/m3
2) From the following standard electrode potentials at 25ºC. Cu2+ + 2e = Cu, Eº = + 0.34 V Cu2+ + e = Cu+, Eº = + 0.15 V
Calculate the equilibrium constant of the reaction Cu + Cu2+ = 2Cu+
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5 Answers
11Ans 2) Dunno if it's correct or not
Cu2+ + 2e- → Cu, ................ Eº = + 0.34 V
Cu2+ + e- → Cu+ ................ Eº = + 0.15 V
Cu + Cu2+ → 2Cu+ ................ E° = + x V
Since e.m.f is an extensive property and it cannot be added whereas change in free enrgy is an extensive prop and these r additive.
Using cahnge in free energy = -nFE° , we get
(2X0.34) + (1 X 0.15) = x
Thus, x = 0.73 V
Using Nernst equation, we get
0.73 = 0.06 ln Q
Thus, ln Q = 12.166 (approx.)
and Q= ......
Someone please verify the answer