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Sorry. I really don't know the answer dude.
5.2g of a limestone was dissolved in dilute HCl and the solution was made up to 1 dm3. 25cm3 of this solution was treated with ammonium oxalate. The resulting ppt. of calcium oxalate was titrated against 0.111N KMnO4 in acidic medium. The end point was 22.2cm3. Calculate the percentage of calcium carbonate in the sample.
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1wel.........its not a bad ques.............u need to start from backwards.......its pure titration of calcium oxalate and KMnO4. from this we can find vol and normality of calcium oxalate and from tht we can find molarity of calcium..........then v can use some dilution formulas and finally cum 2 d starting point.....wher v will get d mass of calcium carbonate in it...........let that be x...........then percentage is x/5.2*100................thts all