yup since ΔTf = Kf mi
i = vant hoff's factor , m = molality , Kf to aaap jante hi hoge
and i =[1 + (y-1)x] where x is degree of dissociation and y is the no. of product molecules yield by 1 mole of reactant [1]
the depression in freezing point (for the same amount of each) is:
acetic acid<trichloroacetic acid<trifluoroacetic acid...explain
NCERT Class XII part 1 pg. 61 q)2.31
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5 Answers
TANAY
·2010-04-08 04:57:13
dep in fpt depends on Kf of solvnt whch depnds on nature of solvnt.
guess its corrct
Avik
·2010-04-08 05:06:25
"i" depends on the Degree of dissociation.
TriFluoro one will ionise the MaX. 'coz of the stabilisation of the -ve charge acquired,, due to gr8test -I effect.
Grandmaster
·2010-04-08 06:16:26
correct avik....
actually for monoprotic acid like acetic acid and its derivatives...
i=1+(alpha)
hence (alpha) proportional to acidic character proportional to depression in freezing point.....(it can be any colligative property!!!)
Manmay kumar Mohanty
·2010-04-08 07:29:52