because of large size of I
and because of small size of H it is not suitable for axial position
Why ICl7 does exist but ClI7 does not?
Why SF6 does exist but SH6 does not?
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8 Answers
I think the 1st happens because I has expansion of octet and so does S. Whereas Cl and H are not able to furnish them.
well, i think : as we go down the group in Group - 17 , the electropositive character and oxidising character increase and so as the capability to show higher positive oxidation states
thus , I can show stable +7 oxidation state , but not Cl.
again, F atom is too small , so hs high coordination number and also hs highly -ve enthalpy, due to which flouride bonds are very strong.
due to these two reasons, SF6 is possible.
I totally agree with you aieeee.But Cl can also show stable +7 oxidation state, as in Cl2O7.
In the first case,size of Cl is much less than I as a result ICl7 exists but not the other. s orbital has lowest energy as compared to p orbital as it is closer to the nucleus. So the mixing of orbitals woluld be a little difficult.In order to achieve this,the fluorine atom comes closer to it and sulphur attains a +ve charge and the orbitals of sulphur atom would come more closer to the nucleus,thus decreasing the energy level and making hybridisation simpler.So SF6 exists while SH6 doesn't.