I solved it today only :P
Let no. of moles of A,B and C at equi. be nA , nB , nC
Then K1= nBnA
and K2=nCnA
so K1+K2= nC+nBnA
adding 1 and inverting we get the answer
- Niraj kumar Jha Thanks!Upvote·0· Reply ·2014-04-29 02:52:12
I solved it today only :P
Let no. of moles of A,B and C at equi. be nA , nB , nC
Then K1= nBnA
and K2=nCnA
so K1+K2= nC+nBnA
adding 1 and inverting we get the answer