Chemical Equilibrium

JEE Mains Tutorials › Physical Chemistry questions › Chemical Equilibrium

Two solids components A and B dissociate into gaseous products at 20Â°C as
i) A(s) â†’ A'(g) + H₂S(g)
ii) B(s) â†’ B'(g) + H₂S(g)
At 20Â°C pressure over the excess solid A is 50 mm Hg and that over excess solid B is 68 mm Hg.
find
a) The dissociation constants of A and B
b) the ratio of the number of moles of A' and B' in the vapor phase over a mixture of solids A and B
c) The total pressure of gas over the solid mixture.

#Chemistry #Physical Chemistry

UP 0 DOWN 0 0 1
Post on FacebookPost anonymously?

1 Answers

Vivek @ Born this Way ·2012-04-04 01:51:38

The dissociation constant is the Equilibrium constant I presume. Now

a)
K_p = P2 . P2 = P²4 , Where P is the total pressure as given and since the molefraction of each component is 1/2.

This expression should be written for both A and B, therefrom you'll get K_p_A and K_p_B

When both are mixed,

A(s) â†’ A'(g) + H₂S(g)
x x+y

B(s) â†’ B'(g) + H₂S(g)
y x+y

Again write K_P_A = P_T x2x+y . P_T(x+y)2x+y and similarly K_p_B , Now you know these quantities and hence you can solve them for x and y (since there are two relations.)

And Subsequently you'll get P_T = Total Pressure.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Chemical Equilibrium

1 Answers

Your Answer

Add Image

Similar Questions