Chemical Equilibrium

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Calculate the equilibrium concentration ratio of C to A if 2.0 ml of each of A and B were allowed to come to equilibrium at 300 K.
A + B C + D
dG = 460 cal

#Chemistry #Physical Chemistry

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4 Answers

661

Gaurav Gardi ·Apr 15 '13 at 21:43

K=[C][D][A][B]
we know that at equilibrium [C]=[D] and [A]=[B]
so k=[C]²[A]²
therefore [C][A]=âˆšK
also K=e^-Î”GoRT
so,[C][A]=e^-Î”Go2RT

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333

Hardik Sheth ·Apr 15 '13 at 5:48

i think the ans is the square root of the given ans by swarna..

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Swarna Kamal Dhyawala how cn u explain?????
Upvote·0· Reply ·Apr 15 '13 at 6:35
Swarna Kamal Dhyawala how cn u explain?????
Upvote·0· Reply ·Apr 15 '13 at 6:35
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996

Swarna Kamal Dhyawala ·Apr 11 '13 at 10:22

(deltaGÂ°)/-RT = lnK

K = e^{-deltaGÂ°/RT}

Ans)1.8 x 10^-4

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Bitan Chakraborty No. Not correct. You have to find [C]/[A]....... Please try again!!
Upvote·0· Reply ·Apr 13 '13 at 6:07
Anurag Ghosh The K dat Swarna evaluated is [C][D]/[A][B].....
Upvote·0· Reply ·Apr 14 '13 at 18:52
Anurag Ghosh Bitan dada....Give sum hint...
Upvote·0· Reply ·Apr 14 '13 at 18:58
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106

Bitan Chakraborty ·Apr 15 '13 at 23:00

@Anurag and @Swarna Kamal: See the above solution. This is how you tackle sums related to equilibrium.
The answer is 0.682.

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