Calculate the equilibrium concentration ratio of C to A if 2.0 ml of each of A and B were allowed to come to equilibrium at 300 K.
A + B 
C + D
dG = 460 cal
661K=[C][D][A][B]
we know that at equilibrium [C]=[D] and [A]=[B]
so k=[C]2[A]2
therefore [C][A]=√K
also K=e-ΔGoRT
so,[C][A]=e-ΔGo2RT
333i think the ans is the square root of the given ans by swarna..
Swarna Kamal Dhyawala how cn u explain?????Swarna Kamal Dhyawala how cn u explain?????996(deltaG°)/-RT = lnK
K = e-deltaG°/RT
Ans)1.8 x 10-4
Bitan Chakraborty No. Not correct.
You have to find [C]/[A].......
Please try again!!Anurag Ghosh The K dat Swarna evaluated is [C][D]/[A][B].....Anurag Ghosh Bitan dada....Give sum hint...106@Anurag and @Swarna Kamal: See the above solution. This is how you tackle sums related to equilibrium.
The answer is 0.682.