3Is the answer 0.3 atm?
The degree of dissociation of PCl(5) at 1atm pressure is 0.2.Calculate the pressure at which
PCL(5) is dissociated to 50%.
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3 Answers
3If it is.. then i think it is like this....
kp=px2/(1-x2)
p1x12/(1-x12)=p2x22/(1-x22)
Therefore:
(1*0.2)/0.96=(p2*0.5)/0.75
so we get
0.15/0.48=0.3 atm
24PCl5 (s)\LeftrightarrowPCl3 (g) +Cl2 (g)
1 0 0
1-α α α Total moles=1+α
Partial pressure(PCl3)=\frac {\alpha }{1+\alpha}P_0=Partial pressure(Cl2)
where P0=1 atm ,α=0.2
Now ,K_P=({\frac {\alpha}{1+ \alpha}}P_0)^2
Solving, KP=4/144
Now KP is dependent on temp only
=> KP=4/144=({\frac {\alpha '}{1+ \alpha '}}P_{new})^2
where Pnew is to be found out and α'=0.5
Solving Pnew =0.25
