Chemical Equlibrium_2

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N₂(g)+3H₂(g)â†’2NH₃

For the reaction initially the mole ratio was 1:3 of N₂ and H₂.At equilibrium 50% of each has reached.Find the partial pressure of NH₃ at equilibrium if the equilibrium pressure is P.

I am getting P/3 as ans..Please verify it..Its an easy one..

#Chemistry #Physical Chemistry

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5 Answers

UTTARA ·2009-10-28 00:32:33

U're ans is right !!

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UTTARA ·2009-10-28 00:34:07

N2(g)+3H2(g)â†’2NH3

1-a 3-3a 2a

Total moles = 4-2a

Partial pressure of NH3 = a/(2-a) x P = 0.5/1.5 P = P/3

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Asish Mahapatra ·2009-10-28 00:40:19

uttara just correct it a bit its a typo

it should be 1-a and not 1-2a

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UTTARA ·2009-10-28 00:41:05

Thanks Ashish
corrected:)

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Rocky Crazy ·2009-10-28 01:05:14

Thanks both of u..

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Chemical Equlibrium_2

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