C2H5OH + CH3COOH = CH3COOC2H5 + H2O
t=0 1 1 0 0
t=teq 2/3 2/3 1/3 1/3
So Keq = (1/3*1/3)/(2/3*2/3) = 1/4 = 0.25
One mole of pure ethyl alcohol was treated with one mole of pure Acetic Acid at 25.C.One third of the acid changes into ester at equilibrium.Find the equilibrium constant for the reaction.
C2H5OH + CH3COOH = CH3COOC2H5 + H2O
t=0 1 1 0 0
t=teq 2/3 2/3 1/3 1/3
So Keq = (1/3*1/3)/(2/3*2/3) = 1/4 = 0.25