Chemical Equlibrium

JEE Mains 2015 Sample Questions › Physical Chemistry questions › Chemical Equlibrium

I₂(aq)+I^-(aq) â†’ I₃^-(aq)

We started with 1 mole of I₂ and 0.5 mole of I^- in one litre flask.After equlibrium is reached,excess of AgNO₃ gave 0.25 mole of yellow ppt.Find the Equilibrium constant of the rxn.

Note--- â†’ represents reversible rxn..

#Chemistry #Physical Chemistry

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Asish Mahapatra ·2009-10-27 09:57:42

at eqbm conc. of I- is 0.25 moles/lit as AgNO3 reacts with 0.25 moles of I- to form AgI

So,
I2 + I- --> I3-
t=0 1 0.5 0
t=teq 0.75 0.25 0.25

So Keq = Kc = (0.25)/(0.25*0.75)
= 1.33 lit/moles

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Rocky Crazy ·2009-10-27 10:00:55

Thanks dude..

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Chemical Equlibrium

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