let initial qty=A
at time t =B
=> change =A-B
for first order reaction,
ln(A/B)=kt
=>A/B=ekt
degree of dissociation=A-B/A
=> 1- B/A
=> 1- e-kt
let initial qty=A
at time t =B
=> change =A-B
for first order reaction,
ln(A/B)=kt
=>A/B=ekt
degree of dissociation=A-B/A
=> 1- B/A
=> 1- e-kt
toatal dissociation is (A-B)
original amount was A
hence the degree of dissociation