chemical kinetics

explain degree of dissociation is 1-e^(-kt)

6 Answers

this means what fraction of the initial compound has dissociated

i meant to say how we got this formula

let initial qty=A
at time t =B
=> change =A-B

for first order reaction,
ln(A/B)=kt
=>A/B=e^kt

degree of dissociation=A-B/A
=> 1- B/A
=> 1- e^-kt

is this for only first order reaction

how degree of dissociation=A-B/A???????

toatal dissociation is (A-B)

original amount was A

hence the degree of dissociation

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