Chemical Kinetics

1)Nitrogen monoxide, NO, reacts with hydrogen, H2, according to the following equation:
2 NO (g) + 2 H2 (g) → N2 (g) + 2 H2O (g)
If the mechanism for this reaction were, 2NO(g) + H2(g) N2(g) + H2O2(g) (fast) H2O2(g) + H2(g) → 2H2O (g) (slow)
which of the following rate laws would we expect to obtain experimentally?

Rate = k[H2O2][H2]
Rate = k[NO]2[H2]
Rate = k[NO] 2 [H2]2

2)Order of a reaction is an experimental quantity. One of the ways of determining order of a reaction is plotting graphs of concentrations of reactants obtained at different intervals of time. A plot of log[Reactant] vs time (min) resulted in a straight line with a slope of – 0.0218.
The rate of the reaction when the concentration of the reactant is 0.3 M is
0.015 M.min-1
0.00654 M min-1
0.05 M.min-1
None of these

2 Answers

13
Avik ·

1) The last one shuld be rite.
(Always remember ki Rate Law exp. mein Intermediate specie ki conc. nahi aani chahiye)

1
utd4ever ·

i know that but i am not able to derive the rate law expression so if you could plzz post the working it would be great ....

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