71It's ought to be second order.
Soumyabrata Mondal how can i prove this???Upvote·0· Reply ·2012-06-12 10:28:44
Rajiv Agarwal Just assume the simple relation r = k[X]^y
then you have, 4r = k[2X]^y
divide them, and get the ans. y = 2
If we doubled the concentration of x In the reaction X→Y, then rate of the reaction become 4 times of it's initial rate. what is the order of the reaction??
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71