(1)How many eletrons in Na( atomis no. 11) satisfy the equation: 2n+l=5m+s where n, l, m, s are the principle, azimuthal, magnetic and spin quantum no.s respectively. . (a)1 (b)5 (c)6 (d) none of these . . .
. (2)Which of the following pairs of orbitals have electronic density along the axis? (a)dxz , dyz (b)dx2-y2 , dz2 (c)dxy , dyz (d)dxy , dz2
(3)The hybridization of P in phosphate ion is the same as in . . (a)I in ICI4- (b) S in SO3 (c) N in NO3- (d) S in SO32
(4)Which of the following combinations in solution CANNOT be a buffer??? (a) HNO2/KNO2 (b) KCL/HCL (c)NH3 / NH4NO3 (d)NaH2PO4/H3 PO4
1(1)
2n + l - 5m=s
I guess n, l, m are integers. Any primary operations on it will produce an integer. Whereas s=+/- 1/2
So, no electron.
Excuse me if its a blunder, but that is what which crossed my mind first. ;)
1(5)One mole of a monoatomic ideal gas goes through the process PT= constant from point A(P1,2T1) to point B(2P1, T1). The work done during the process is . . . . . . . (given T1=300K). . . . . . (a)600R units (b) 900R units (c)1200R units (d) none of these. . .
39The first question seems correct the way you solved it, Ray. Indeed, spin number for fermions(electrons) is ±1/2, which is not an integer. LHS can never be equal to the RHS.
1i dnt actually knw all the answers properly. . i got it and posted it. . i solved some of them too. . i thnk the last one mght b 4(c). . i m not sure .
1oh. . i thought u r talking abt the buffer one. . . yes the last one is (d). .
1(6) 90gm of a metal reacts with 40 gm of oxygen to form metal oxide(M2 OX). The metal oxide requires 10 L of 1/3N of oxidizing agent to oxidise to M5+ . find molecular weight of the metal. . . (a)72 (b)18 (c)54 (d)36
(7) In a container oxygen and hydrogen are present. some weight of gases escapes. Niw same weight (gas escaped) of methane is added so that the total pressure of the mixture remains same. The weight percent (of gas escaped) of hydrogen escaped is (a)3.33% (b)6.66% (c)1.67% (d)13.36%.
