this image should help
If CO Bond length = 1.128 Angstorm, then the possible value of CO bond length is Fe(CO) is
(a) 1.128 A
(b) 1.10A
(c) 1.13 A
(d) 10115A
I do not understand how the d pi- p pi bonding will affect eh bond order of CO bond….????
-
UP 0 DOWN 0 1 12
12 Answers
d pi- p pi backbonding : the bond order increases (as there is partial extra bond character ) which decreases the bond length. so the bond length of M-CO will be slightly less than CO bond length
So answer is (b)
The M–C π bond is formed by the
donation of a pair of electrons from a filled d orbital
of metal into the vacant antibonding π* orbital of
carbon monoxide. so due to donation of electrons in antibonding orbital ..bond order decreases so bond length increases
Actually i think this is a past IIT question..
the answer is definitely 1.13A° ..
well i have seen somewhere it was given as a multiple correct question ..and there one of the options given was 1.70 and it was correct..the reason given was that due to addition of electrons in the antibonding orbitals the bond length will increase...but i dont think it will increase this much..
Please someone confirm it...
yes its syngeric bonding in metal complexes
refer ncert where it is explained clearly
@Tom...
Ya i know all abt this...I just want to confirm whether the bond length will increase from 1.128A to 1.70A in case of synergic bonding??...
@Tom...arrey yaar u r not getting my point...in JD Lee it's written that bond length increases from 1.128A to 1.15A..and my dbt is will the bond length increase upto 1.70A due to synergic bonding?
Well what I've studied about bonding in metal carbonyls...the bond length increase happening due to synergic effect is because the bond order of C - O is reduced from triple to double bond. Thus bond length increases to 1.5 A in many carbonyls...nowhere did I see an example of 1.70 A..thats a bit too much I think.
@Pritish where have u studied that it increases upto 1.5A ..i guess that figure shud be 1.15A..that's wat JD Lee says..anyways thanks for the reply..