11Let The misture be of 0.8moles of O2 and 0.2moles of X
r1/r2=√d2/d1
234/224 = √0.8*32 + 0.2*X/0.8*32/0.8
234/224=√0.8*32+0.2*X/32
117/112=√0.8 +X/160
X = 46.604g
A gaseous mixture of O2 and X containing 20% (mole%) of X, diffused through a small hole in 234 second, while pure O2 takes 224 seconds to diffuse through the same hole. Find the molecular weight of X ???????????
Please explain elaborately....
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