WITH t TIME TAKEN IN SECONDS AND I TAKEN IN AMPERE THE VARIATION OF I FOLLOWS THE EQUATION t2+I2=25.WHAT AMOUNT OF Ag WILL BE ELECTRODEPOSITED WITH THIS CURRENT FLOWING IN THE INTERVAL 0-5SEC.Ag-108.
A 22mg
B 66mg
C 72mg
D 88mg
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1 Answers
62if you plot I vs T, the equation will be of a quarter circle..
The area gives the charge flow...
The area is pi r^2/4 = .449 C
now the n factor for Ag is 1
so the no of electrons flow is equal to the number of Ag Atoms deposited..
so The moles of Ag deposited = .449/(eN) (Where e is the charge of electron while N is the avagadro's number)
6.023 × 1023x 1.6 x 10-19 = 9.63x104
Multiply by 108 to get the no of grams of Ag
I am getting 73 mg..
