thse are the reactions......try to get the ans now...
8HClO3 → 4HClO4 + 2H2O + 2Cl2 + 3 O2
H2O +SO2 →H2SO3
4 H2SO3 +2Cl2 →4H2SO4 +Cl2
Cl2 +H2O→HCl+HClO
How many litres of SO2 has to be passed through HClO3 to reduce 16.9 g of it to HCl..
Ans 13.44
thse are the reactions......try to get the ans now...
8HClO3 → 4HClO4 + 2H2O + 2Cl2 + 3 O2
H2O +SO2 →H2SO3
4 H2SO3 +2Cl2 →4H2SO4 +Cl2
Cl2 +H2O→HCl+HClO
ye complex equations yaad karna padega ya fir koi aur method hai.............help yaar[21][21][21]
@ eureka : Can't v solve this qs in any other way other than remebering those equations ???
other way means ????u need to know tha eraction to solve mole concept ques
@UTTARA...no it's not necessary for u to remember these equations..
Simply do what the question is asking..
HClO3 + SO2 → HCl + H2SO4 ...
now balance the equation..add water to one side..
3H2O + HClO3 + 3SO2 → HCl + 3H2SO4 ...
Moles of HClO3 given = 0.2
Moles of SO2 required = 0.6
In the question it shud be given that SO2 is at STP..then only the answer will be 13.44 Litres
I hope this one is an easy solution
i know a simpler process...
the process is 1 gram equivalent of substance A reacts with 1 gram equivalent of substance B to give 1 gram equivalent of substance C and 1 gram equivalent of substance D..
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this may kill the question most easily!![3][3]
no sb that did'nt work,.... i tried it ... i did that first
@Aditya ..
wat abt the temperature and pressure conditions given in the question? If the SO2 gas is produced at STP then only the answer will be 13.44 Litres..