\Delta G=\Delta H -T\Delta S\ and \Delta \ G=\Delta H +T[\frac {d(\Delta G)}{dT}]_P
then find (\frac {dE_{cell}}{dT})= ??
106ΔG = -nFEcell
differentiating it wrt T,
d(ΔH-TΔS)/dT = -nF*d(Ecell)/dT
=> -ΔS = -nF*d(Ecell)/dT
=> d(Ecell)/dT = ΔS/nF
now frm the two relations that uve given abv, ΔS = -T[d(ΔG)dT]p
So put in abv equation
Btw, d(Ecell)/dT is known as temp coeff. of the cell
24ya its 99.99999% not in syllabus.but i found this ques 2 days back and couldnt work it out..so thought if someone is preparing for olympaid type thing can help me our
