1mera ans bhi yehi aa raha tha paar aapne first line main 2 multiply kiske liye kiya hai iodine or thiosulphate....
A constant current flowed for 2 hours through a potassium iodide solution oxidizing the iodide ion to iodine
2I- -> I2 + 2e-
At the end of the experiment, the iodine was titrated with 21.75 ml of 0.0831 M sodium thiosulphate solution
I2 + 2S2O32- -> 2I- + S4O62-
WHAT WAS THE AVERAGE RATE OF CURRENT FLOW IN AMPERES??
ANS :- 0.0242 A
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4 Answers
6221.75 x 0.0831 x 2 milli moles of electron!
21.75 x 0.0831 x 6.023 x 1023 x 10-3 x2 electrons
21.75 x 0.0831 x 2 x 6.023 x 1023-3 x 1.6 x 10-19 x2 couloumb of charge...
in 2 hours = 7200 seconds
current will be ... 0.0242x2 A
am I making some mistake??
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