Electrochemistry


I am really weak in chemistry ,so don't get upset abt the level of ques.

7 Answers

1
Sonne ·

hello

the first question

Cu2++2e--->Cu

Ecell=E0cell - .0592log1[Cu2+]
now replace [Cu2+] by [Cu2+]10

E'cell=E0cell - .0592log10[Cu2+]

subtract both

hence decrease by .0592=29.5 mV answer is C

11
vaibhav sharma ·

@cool rocks
u mean (d)?

1
Sonne ·

2nd question

at equilibrium ΔG=0 so is Ecell

now write nernst equation and solve the question

1
Sonne ·

yes vaibhav i mean d

1
rahul1993 Duggal ·

3.
we have ΔG=-2.303RTlogK
also ΔG=-nFE
equating the above, 2.303 x 8.314(J/molK) x 298(k) x log(2.69x1012) = 2 x 96500(F\mol) x E
so you can calculate E

1
ajoy abcd ·

so are you getting exact .1836V as answer??

1
rahul1993 Duggal ·

the above working should give the correct ans. i havent calculated

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