11.LET DER INITIALLY B 1 MOLE EACH OF PCL5 AND CL2..
AT EQUIM.
PCL5 HAS 1-X MOLES
PCL3 HAS X MOLES
CL2 HAS 1+X MOLES
TOLTAL=2+X
(x)(1+x)P(1-x)(2+x)=2...where P=2
solve for x ...it will give 0.5..approx.....
% dissociation=50%
Q1 PCl5 is added to flask containing Cl2 at 1 atm and 500K is sealed where eqb is established.Kp=2 atm.Determine % dissociation of PCl5 if eqb pressure is 3 atm..
Q2 1 mole of N2 and 3 mole of PCL5 are taken in a 100 L flask and heated 20 227 C where total pressure at eqb is found to be 2.05 atm.Determine Kp for reaction assuming N2 to be inert
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4 Answers
11N2 DOESNT REACT
AT EQUIM.
PCL5 HAS 3-X MOLES
PCL3 HAS X MOLES
CL2 HAS X MOLES
TOLTAL=3+X+1=4+X...FROM N2
(x)2P (3-x)(4+x)=Kp
NOW USE PV=NRT..N=4+X
..>X=1
SO Kp=0.205.......APPROX
GUYZ...PLZ BEAR WITH ME FOR ALL CALC.. MISTAKES
