plz help me out in these doubts..:
1. how can u explain the concept dat when a reaction shifts in the forward reaction, the greater concentration of products are formed.. and vice versa.... why does this happen.... plz tell me....
2. Reaction A + B = C + D + 38 kcal has activation energy 20 kcal . Then the activation nergy for the reverse reaction.... will be :
(a) 20 (c) 18
(b) -20 (d) 58
<sry... cud nt get any hint in this>
3. When NaNO3 is heated in a closed vessel, oxygen is liberated and NaNO2 is left behind. At equilibrium:
(a) Addition of NaNO2 favours reverse reaction
(b) Addition of NaNO3 favours forward reaction
(c) Increasing the temperature favours forward reaction
(d) Increasing the pressure favours reverse reaction
I answered this question as (b),(c) and (d).... but the ans given in the buk is only (c) and (d)... can't the ans be (b).. nd wht abt (a)....
1063. Hint : NaNO3 and NaNO2 are solids
2. Hint: try to draw the energy profile for this reaction
1sorry asish..... bt plz tell me.... wht if they are solids??????? the only thing is dat their conc will be unity.....
133) ...And their conc. will be considered unity no matter wht amount u put it, which wont affect the reaction in any way.
2) Drawing the engy curve u'll see tht fr any reaction- ΔH= Eact(forward) - Eact(backward)
(with appropriate signs of course)
Isse we get d)58 as the answer.
1) Didn't get the Qn.