equilibra

plz help me out in these doubts..:

1. how can u explain the concept dat when a reaction shifts in the forward reaction, the greater concentration of products are formed.. and vice versa.... why does this happen.... plz tell me....

2. Reaction A + B = C + D + 38 kcal has activation energy 20 kcal . Then the activation nergy for the reverse reaction.... will be :

(a) 20 (c) 18
(b) -20 (d) 58
<sry... cud nt get any hint in this>

3. When NaNO3 is heated in a closed vessel, oxygen is liberated and NaNO2 is left behind. At equilibrium:

(a) Addition of NaNO2 favours reverse reaction
(b) Addition of NaNO3 favours forward reaction
(c) Increasing the temperature favours forward reaction
(d) Increasing the pressure favours reverse reaction

I answered this question as (b),(c) and (d).... but the ans given in the buk is only (c) and (d)... can't the ans be (b).. nd wht abt (a)....

3 Answers

106
Asish Mahapatra ·

3. Hint : NaNO3 and NaNO2 are solids

2. Hint: try to draw the energy profile for this reaction

1
venkateshan ·

sorry asish..... bt plz tell me.... wht if they are solids??????? the only thing is dat their conc will be unity.....

13
Avik ·

3) ...And their conc. will be considered unity no matter wht amount u put it, which wont affect the reaction in any way.

2) Drawing the engy curve u'll see tht fr any reaction- ΔH= Eact(forward) - Eact(backward)
(with appropriate signs of course)
Isse we get d)58 as the answer.

1) Didn't get the Qn.

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