1ans is 4
A reaction A + B C + D. Initially, we start with equal concentration of A and B, At equilibrium we find the moles of C is two times of A. What is the equilibrium constant of the reaction?
1/4
2
4
1/2 xplain clearly
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2 Answers
1let the initial moles of A and B be c
at equillibrium let x moles of A (and thus the same of B) be gone
A + B => C+D
c-x c-x x x
we have
2(c-x)=x
thus x=2c/3
thus at equillibrium con. of A= c/3 B= c/3 C=2c/3 and D=2c/3
thue we get equillibrium const. as four