Q:3A complex of Zn has the formula [Zn(NH3)x]Cl2 and on reaction with HCl forms NH+4 ions as :
[Zn(NH3)x]Cl2+HCl → Zn2+ + NH+4+Cl-
1.02 g complex was treated with HCl and at the end point solution was treated with excess of AgNO3 solution giving 0.4305 g AgCl precipitate. Determine x and volume of 1.0 M HCl used up.
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