equivalent weight

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hey guys could anyone explain how to find equvalent weight in reaction such as,

example 1-

4KMnO₄ + 5HC₂O₄.H₂C₂O₄.2H₂O + 13H₂SO₄ â†’ 4MnSO₄ + 9KHSO₄ +20CO₂ + 18H₂O

the equivalent weight of potassium tetraoxalate crystals are?
a-84.76
b-63.5
c-127
d-158.75

answer given is option b

example 2-

find the equivalent weight of K₂Cr₂O₇ (molecular weight=M)

reaction

K₂Cr₂O₇ + HCl â†’ KCl + CrCl₃ + Cl₂ + H₂O

my question is why do we need to balance the reactions only in some reactions to find the equivalent weight .

Regards,
gp

#Chemistry #Physical Chemistry

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4 Answers

Vivek @ Born this Way ·2012-04-04 02:39:33

In case of redox reactions,to calculate the equivalent weight of a particular compound, you need to calculate the n-factor. But for that you'll have the write up the oxidation and reduction reaction which in turn are used for balancing the reaction.

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Vivek @ Born this Way ·2012-04-04 02:43:23

In Non redox reaction, the Equivalent weight is simply like E = M/No of H atoms lost (for acids) and so on.

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funkygp ·2012-04-04 04:34:12

could you give the method of finding the nfactor after balancing the rxn.
(i can't recall the method of doing it)

thanks,
gp

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Vivek @ Born this Way ·2012-04-04 11:17:44

please search for it on google or on go iit.

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Basic Integral Calculus Operators Symbols Matrix Cases

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∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

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° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

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equivalent weight

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