Ex-IIT ques..pls help!!

IIT JEE 2015 Coaching › Physical Chemistry questions › Ex-IIT ques..pls help!!

1. 0.1 mole of CH3NH2(k_b=5*10^-4) is mixed with 0.08 mole of HCl and diluted to 1 L.What wil b the H+ concentration in solution?

a. 8*10^-2 b. 8*10^-11 c. 1.6 *10^-11 d. 8*10^-5

#Chemistry #Physical Chemistry

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8 Answers

21

tapanmast Vora ·2009-04-10 12:06:40

A

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1

Aditya ·2009-04-10 12:10:20

Arrey i too thot that but ans is given to be b.....

Basically the H+ conc wud b only due to HCl na, which wud completely dissociate???

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11

Mani Pal Singh ·2009-04-10 12:11:39

CH₃NH₂+HCl----------->CH₃NH₃⁺Cl^-

0.1 0.08 0
0.02 0 0.08

p^OH=pK_b+log[0.08]/[0.02]....................Henderson equation
=> 3.3 +0.602=3.902

p^H=14-3.902=10.09

[H⁺]=7.99 X 10^-11=8 X 10^-11M

bhai adi maine yeh dekh kar samjha hai
par ab samajh aa gaya hai

I CAN EXPLAIN IN CASE OF DOUBT[1]

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1

vector ·2009-04-10 12:11:58

h+ wud be cnsumed by the base also na

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21

tapanmast Vora ·2009-04-10 12:12:11

wich year's Que is it?

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21

tapanmast Vora ·2009-04-10 12:13:33

Oh!!! yah!!

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vector ·2009-04-10 12:14:22

nice wurk mani

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Aditya ·2009-04-10 12:15:02

thanx Mani....it's of year 2005

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