262contradictory posts there.
but i am very sure of this fact. our fiitjee teacher told this in class .
and i have also seen a similar question in a mock test whose ans. is also NO+
Q In complex [Fe(H2O)5(NO)]2+ , NO molecule is present as :
Attempt: The answer given is NO+, But I think here NO is neutral.
Q An equimolar mixture of toulene and chlorobenzene is treated with a mixture of Conc. Nitric acid and Sulfuric Acid , then
Attempt: Answer given p-nitrotoulene is major Product.
I do ntot agree to this. I think It should be p-nitrochlrobenzene is formed in excess.
Q With which the Friedel Crafts Reaction takes place moer efficiently :
Acetophenone or Toulene ?
Q: Which is correct :
a) Radius Ca2+ < Cl - < S2-
b) Radius Cl - < S2-< Ca2+
c) Radius of S2- < Cl - < Ca2+
I think it should be B , the answer suggests A ? What should it be?
-
UP 0 DOWN 0 0 19
19 Answers
2622621/3 of the total marks are deducted .
i am expecting arond 175.
71@ Subhodip,
I don't say your answer is wrong. But the post #12 isn't wrong either. The reference which the books (eg JD Lee) make to the complex, do not make them under the conditions of Brown RIng test.
@Aditya, 2/3 marks were deducted na? So 2/3 of the marks of the question or 2/3 of 1 ?
By the way, How much are you expecting/?
71Yes, And Don't know why I think that they will use NO+ as answer. Let's see. If wrong it will take away -3.33 marks . :(
71Aditya!
What you FIITJEE teacher told is correct, But in context of Brown RING COMPLEX, the NO is neutral. It does not mean that your statement is wrong. The user there again wrote :
" To clarify my point. My two posts were an attempt to show that there is not contradiction between different answers. Both Fe(I) and Fe(II) complex exist. It depends of the conditions!
The answer NO+ given in the answer section of your 'homework' is correct, because [Fe(H2O)5(NO)]2+ is the typical example of a Fe(I) complex with electronic configuration d7.
At the same time, as Borek pointed out, a complex [Fe(H2O)5(NO)]2+ of Fe(II) with configuration d6 is formed under the conditions of the brown ring test."
7For the last q ans should be a , vivek..Here all the species r iso-electronic. all have their last shell or rather 3p orbitals fully filled. now Ca2+ is the smallest since here the electron cloud is most pulled by the electrostatic force of attraction of the protons(here in excess to the no. of electrons.and the radius becomes smaller than those of S2- and Cl- which hav an excess of elctrons over the no. of protons. Now electron-electron repulsion is more in S2- than Cl-
71Aditya, For NO one, Please see this http://www.chemicalforums.com/index.php?topic=58138.0;topicseen
262it is an experimental observation . i dont think there is any particular reason (at least at our level) .
7Yes, Aditya, i guessed that too but dn't know the reason behind it. Aditya, do u knw the reason?
262AlCl3 coordinates with oxygen in acetophenone, and as it is carbonyl group is a deactivating group.
2622) chlorine being a highly electronegative halogen , decreses electron density due to inductive effect.
2621) this complex is an exception where iron exists as Fe1+ . thus it is NO+