1delta G0 becomes +ve and -ve acc to temperature for ex in an exothermic reaction on inc temp reaction may become non spontaneous and δG0 might become +ve
does delta G(not) change with temp...thou it is defined at 298K only
.Q.. 2 A(g) + B(g) (equlibrium) 3S(s) + T(g)
delta H(not) = -145
At 298K forward rxn is spontaneous, wt change if ny wud occur in deltaG(not) value as temp. is inc
.a. becomes positive
b. doesnt change
c. becomes neg.
-
UP 0 DOWN 0 0 13
13 Answers
11deepanshu in that Q of urs i dont think if spontanity is playing any role thats y any change in temp will not effecy G0
13u mean 2 say delta G(not) doesnt change wid temp....
dats wt i tryin 2 gt a clr idea abt
13the ans is dat it becomz more positive can ny explain...
i m nt gettin it at ol
13cant use that relation... bcz even K changes wid temp
using
dG(not)=d H(not) - dS(not)
u do get the ans given bt wt i intend to ask is that is that dG(net) is changin
wid change in temp.. though it is defined only at 298K....????
1ACTUALLY as h is -ve so reaction is exo an on increasingt it ll go backward n thus G° going +
13i already noe that but.....
how is it so dG(not) is changin wid temp....???
1as temp is increasing n rate of backward n forward reactin is changing so suppse at a higher temp t" a new value of G° will be defined giving idea abt fissiblity of f reaction at that temp