m getting 82.4 gm
1.12 ml of a gas is produced at S.T.P. by the action of 4.12 mg of alcohol, ROH, with methyl magnesium iodide. find the molecular mass of alcohol.
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3 Answers
Swarna Kamal Dhyawala
·2013-02-28 07:17:19
81.4 gm/mole
Swarna Kamal Dhyawala sorry 82.4gm/mole
Upvote·0· Reply ·2013-02-28 07:45:26
Soumyabrata Mondal
·2013-02-28 07:38:25
ROH+CH3MgI= CH4+ROMg+I
MOLES OF CH4(GAS)≡5*10-5
now (5*10-5) mole of ROH is 4.12 mg
1 mole of ROH = 82.4 gm