overall O.S of FE = +2
let there be 'x' molecules of Fe in +2 O.S then 0.93-x will be in in +3
=> 2*x + 3*(O.93 - x) = 2
=> x = 0.79
=> 0.14 Fe(III) => 0.14 / 0.93 * 100 % = 15 % appx.
A sample of wusite Fe.93O1.00..find the % of Fe(III)in the sample...
-
UP 0 DOWN 0 0 1
1 Answers
rishabh
·2011-07-11 03:42:31