1i think no CO2 should escape.
A bulb is filled with 20g of CO2 gas at 296Kand 1atm.The bulb is heated to 336K,and the stopcock is opened.How much CO2 escapes,if the external pressure is 1atm when the stopcock is opened and the bulb is kept at 336K?When the pressure inside the bulb reaches 1atm,the stopcock is closed again.
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12 Answers
24is last sentence complete?????
""When the pressure inside the bulb reaches 1atm,the stopcock is closed again.""
1oops!!!!!!!!!!!did not read the ques properly that temp. is changed by heating.
1volume of bulb=20*R*296/44
so,final no. of moles in bulb=20*296/(336*44)
so,final weight of CO2 in bulb=17.619 g
so amount of CO2 escaped=2.38=2.4g
6how did u get volume of bulb=20*R*296/44 and final no. of moles in bulb=20*296/(336*44)???
1use ideal gas equation PV=nRT at initial temp.
and then at final temp.
11v1/t1=v2/t2
V/296 = V2/336
V2 =336V/296
V2 = 1.135V
Since the bulb holds only 1V
The escaping volume is 0.135V
1.135V is 20g
0.135V is
20*0.135/1.135
= 2.378g
= 2.38g
6thx for the answer guys ........but....how did u get the idea that u should use charles law???is there any other method???Or instead of telling me the answers plz tell me how to thhink over the problems n help me improve my problem solving skills......plz help!!!!!