12)
14 Answers
491) TaMb=TbMa
or, TaMa=TbMb
or, 32kTaMa=32kTbMb
or, EaMa=EbMb
so option c) ke per mole...[1][1]
492) since all conditions are same, therefore, the pressure is also same so no change in dimensions...:)
1srry shubho bhaii but the answers r not correct the answers given r 1)d nd 2)b
1ohh haan ab aa gaya samjah mein 1)ka toh d he hoga...........for 2nd i used the concept of diffusion but dont noe how to decide ki hydrogen balloon ke andar diffuse karegi ya ethylene........
1is it due to the fact tht mass of hydrogen is less so it ll diffusse more than ethylene.......??????
1thnxx abhirup,rocky nd pritish bhaiiya mcopying the answer to the 2) ques as told by pritish bhaiyaa::Rate of diffusion is inversely proportional to square root of molar mass of gas(Graham's Law). As the molar mass of hydrogen is much lesser than ethylene, it is hydrogen which diffuses faster into the balloon, causing a net change in amount of gas towards the inside. Which is why the balloon inflates!
13)
how to calculate this one..............i thnik it s very easy nd formula puttin ques but don noe not strikin to my mind
39The van der Waals constant 'b' is the volume correction, as you may well know. What the lesser known fact is that it is also called the excluded volume, or co-volume of the molecule. It is 4 times the actual volume of the molecule multiplied by Avogadro number, assuming the molecule to be spherical.
So V x 4 x NA = 24 mL
Use the normal formula for the volume of a sphere and substitute R = D/2.
So V = pi D36