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35) At 80° C , the vapour pressure of pure liquid 'A' is 520 mm Hg and that of pure liquid 'B' is 1000 mm Hg. If a mixture solution of 'A' and 'B' boils at 80° C and 1 atm pressure, the amount of 'A' in the mixture is (1 atm = 760 mm Hg)

1 ) 34 mol percent
2 ) 48 mol percent
3 ) 50 mol percent
4 ) 52 mol percent

5 Answers

1
Dharun ·

ans c

1
°ღ•๓яυΠ·

method

11
Mani Pal Singh ·

520X +1000(1-X)=760
480X=240

X=1/2

1
Dharun ·

760=XaPa+XbPb

Xb=1-Xa

solve it u get the ans

1
°ღ•๓яυΠ·

hehehehehe..............kuch jyaada hi chindi sum tha :P

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