sorry ans is 2.697g
An aqueous solution of methyl amine has pH value 10.64.How many grams of methyl amine are present in 100mL of the solution.Kb=4.4*10-4
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3 Answers
Shailesh
·2008-11-01 06:05:18
-log[H+]=10.64
[H+]=2.29*10-11
Kb=[OH-][CH3NH3+]/[]CH3NH2]
[CH3NH2]=4.33*10-4=mol/litre
Wt.=Molarity*vol*M=4.33*10-4*(100/1000)*31
=1.34 mg
Kumar Saurabh
·2008-11-01 12:41:44
Is the question about initial weight of methyl amine or at equilibrium
initially Wt=2.697 mg (not g)
At equilibrium Wt.=1.34 mg