[HIn]/[In-]=0.1 so we can say that [In-]/[HIn]=10
H+=10-10.5given
Ka=(H+*[In-])/[HIn] put the values and get the ans
An indicator changes from blue to colourless at pH=10.5 as acid is added.At this pH the ratio of acid top salt(conjugate base) is 0.1 i.e [HIn]/[In-]=0.1.Estimate Ka
plzzzz give the soln too .....ur answeer is correct...........plzzzzz
[HIn]/[In-]=0.1 so we can say that [In-]/[HIn]=10
H+=10-10.5given
Ka=(H+*[In-])/[HIn] put the values and get the ans