1molar concentration of NaOCl = 5/(100M)=1/(100*74.5) = 1.34*10-4
so pH=-1/2(logKw+logKa-logc)
=12.7
Determine pH of a 5% aqueous solution of NaOCl(by weight).Density of solution is 1 g/cc.Ka=3*10-8
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3 Answers
1
1357Molar concentration of NaOCl = n/V=w/M/(Wsolution/d)=(w/Wsol)*d/M=(w/Wsol)*d*1000/M (d is in g/cc)
[NaOCl]=(5/100)*1000/74.5=50/74.5=0.67
Now find pH
it should give the answer