Ionic Equilibrium

A Solution M prepared by mixing 300mL of 0.40M weak monoprotic acid HA (Ka=5.0 x 10-6) and 200mL of 0.5M HCl. if 500mL of 0.28M NaOH is added to solution M,the final pH is

the answer is integer type (0-9) solve karo yaron immediately.

2 Answers

106
Asish Mahapatra ·

0.1 moles of HCl
0.14 moles of NaOH
0.12 moles of HA

we get 0.08 moles of HA and 0.04 moles of NaA

so pH = pKa + log([salt]/[acid]) = 5

1
anand sinha ·

thnxie

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