0.1 moles of HCl
0.14 moles of NaOH
0.12 moles of HA
we get 0.08 moles of HA and 0.04 moles of NaA
so pH = pKa + log([salt]/[acid]) = 5
A Solution M prepared by mixing 300mL of 0.40M weak monoprotic acid HA (Ka=5.0 x 10-6) and 200mL of 0.5M HCl. if 500mL of 0.28M NaOH is added to solution M,the final pH is
the answer is integer type (0-9) solve karo yaron immediately.
0.1 moles of HCl
0.14 moles of NaOH
0.12 moles of HA
we get 0.08 moles of HA and 0.04 moles of NaA
so pH = pKa + log([salt]/[acid]) = 5