500 ml of 0.2 M aqueous solution of acetic acid is mixed with 500 mL of 0.2 M HCl at 25 C.
If 6 g of NaOH is added to the above solution,determine the final pH.(Assume no change in volume on mixing)
Ka(CH3COOH) = 1.75 x 10-5 mol/L.
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2 Answers
1357CH3COOH+HCl+NaOH→CH3COONa + NaCl+H2O
moles 0.1 0.1 0.15 0
moles 0.05 0 0 0.05
we have [CH3COOH]=[CH3COONa]
so pH=pKa