natural oxygen consists of 2 types of atoms one having a mass of 16 and the other having a mass of 18,these atoms are found in what proportion???
11shivani
oxygen contains more isotopes
16O--------------->99.757
18O---------------->0.038
4 MORE INFO
http://en.wikipedia.org/wiki/Isotopes_of_oxygen
1ya,actually i have the question but cud not post it as thres no option for writing the mass no and atomic no neways em giving the question try to understand the symbols
Average atomic mass of a sample of an element X
is 16.2 u. What is the ratio of the isotopes16/8 X and 18/8 X
(16/8 means 16 is the mass no. and 8 is the at. no)
(a) 9 : 1 (b) 1 : 9 (c) 6 : 1 (d) 1 : 6
106see .average atomic mass = (m1*X1 + m2*X2)/(X1 + X2)
where Xs' are the proportions in which they are found .. this is for two isotopes and X1 + X2 = 1 (taking in fractional ratios)
==> 16.2 = [X*16 + (1-X)*18]/1
==> 16.2 = 18 - 2X
==> 2X = 1.8
==> X = 0.9
So. ratios of 16 to 18 is X:(1-X) = 9:1
