Just a second 1

Ans A

A certain volume of ethylene after partial reduction with hydrogen in presence of a metal catalyst required 10% more oxygen for complete combustion than it would have originally. Calculate the ethane: ethylene ratio after partial reduction.

3 : 2

2 : 3

7 : 6

6 : 7

1 is clearly b

For (1)

If the curve is steeper it means irreversible no ?? ( I am somehow confused over this)

Cud u plzz explain 1

For (3)

r8 ans

Thanks

ΔG<0 is irreveresible

ΔG≈0 reversible

ok fine

Any tries for 2 n 4 th qs ????

I think hydration is least effective in case of chloral...it would cause S_N instead of nucleophilic addition.

C2H4 INITIALLY LET a moles

C2H4→→C2H6
a(1-x) ax

C2H4+ 3O2→→2co2 +2H2O

C2H6 + 3.5O2→→2co2 +3H2O

total moles of oxygen used after partial reduction=3a+0.5ax(i.e 3a(1-x)+3.5ax)

now 0.5ax=(10/100)*3a

so x=3/5
reqd. ratio = x/1-x
that is 3:2

Q1........

if steeper the curve, higher is the activation energy, slower is the rate of reaction.
Therefore, ans has to be either of c or d, but c n d r lukin identical.....aren't they?

if v luk at de graph c n d.......E_a of reactant and E_a of intermediate is nearly same, indicates that the rate of forward reaction is equal to rate of backward reacion....... means reation is at equilibrium.......

Q4......

I think rocky is rite.......