Kinetics 1992

AIEEE 2015 Guidance › Physical Chemistry questions › Kinetics 1992

The nucleidic ration,³H₁ to ¹H₁ is 8.0 x 10^-18:1.Tritium undergoes decay with the half life period of 12.3 yrs.How many tritium atoms would 10g of such a sample contain 40 yrs after original sample is collected ?

#Chemistry #Physical Chemistry

UP 0 DOWN 0 0 4
Post on FacebookPost anonymously?

4 Answers

virang1 Jhaveri ·2010-02-15 22:57:33

See
H3/H1 = 8.0*10^-18
H1 = k
H3 = 8.0*10^-18k
Therefore
k + 24*10^-18k = 10
k â‰ˆ10
Therefore initial H3 = 80*10^-18

k=0.693/12.3
kt = 2.303logA_i/A_f
t= 12.3/0.3010 (log80*10^-18/A)

Finally there will be 8*10^-18 atoms left

UP 0 DOWN 0
Post on FacebookPost anonymously?

Gone.. ·2010-02-15 23:01:06

virang ans given is 5.624 x 10⁵ atoms.

UP 0 DOWN 0
Post on FacebookPost anonymously?

Manmay kumar Mohanty ·2010-02-16 00:11:18

yaar virang 10^-18 atoms is absurd.

UP 0 DOWN 0
Post on FacebookPost anonymously?

1357

Manish Shankar ·2010-02-18 21:57:34

virang forgot some avagadro number there

UP 0 DOWN 0
Post on FacebookPost anonymously?

Your Answer

Basic Integral Calculus Operators Symbols Matrix Cases

√ √ || {} [] () → ~ ^ x x x → → ln log lg lim lim cos sin tan cot arcsin arccos arctan

∫ ∫ ∫ ∫ ∫ ∬ ∬ ∬ ∬ ∬ ∭ ∭ ∭ ∭ ∭ ⨌ ⨌ ⨌ ⨌ ⨌

∑ ∑ ∑ ∑ ∑ ∮ ∮ ∮ ∮ ∮ ∏ ∏ ∏ ∏ ∏ ∐ ∐ ∐ ∐ ∐

+ - × ÷ ± ∓ = ∪ ∩ ≠ ∼ ≈ ∅ ∀ ∃ ∈ ∋ ∝ ≤ ≥ ≃ ≅ ≡ < > ≪ ≫ ⊂ ∉ ⊃ ⊆ ⊇ ⇒ ⇐ ⇔ ⇒ ⇐ ⇔ ⇑ ⇓ ⇕ → ← ↔ → ← ↔ ↑ ↓ ↕ ↖ ↗ ↘ ↙ ↪ ↩ ⇀ ↼ ⇁ ↽

° ∂ ∞ α β γ δ θ λ μ ν ξ π ρ σ φ ω ε ƒ κ τ υ Γ Δ Λ Σ Π Ω

Close [X]

Kinetics 1992

4 Answers

Your Answer

Add Image

Similar Questions