For ideal gas PV=nRT, Z = PVnRT
for real gas (P + nav2)(V - nb)=nRT
Ideal gas can't be liquified by applying any pressure and temperature.
Q) For one mole of ideal gas (dPdT)v(dVdT)p(dVdP)T = ?
A) -R2P2 B)-RP2 C) -R2P D) -RP
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5 Answers
29for one mole of ideal gas PV=RT
so \frac{dP}{dT} = \frac{R}{V}
\frac{dV}{dT} = \frac{R}{P}
and since temp is constant.PdV + VdP = 0
so \frac{dV}{dP} = -\frac{V}{P}
on multiplying all of these u will get - \frac{R^{2}}{P^{2}}
So ans is A
1govind tera post clear nahin hai.Tera latex equation nahin aaya hai.
1@ manmay..just use ideal gas eqn ....and keep diffentiatin'...kepin da reqd..constant...den multiply....u ll get da ans....A
1arre manmay..isme kya samajh mein nahi aa raha hain??
govind ne jo likha hai..dats da ans....
RV*RP*-VP=-R2P2