the pressure in a vessel that contained pure oxygen dropped from 2000 torr to 1500 torr in 55 min as the oxygen leaked through a small hole into a vacuum.when the same vessel was filled with another gas,the pressure dropped from 2000 torr to 1500 torr in 85 min.what is the molecular weight of the gas ??
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1 Answers
1r1r2 = rate of diff of O2rate of diff of gas X = v1*t2v2 * t1
v1 --> Vol of of O2 Diff.
t1-->Time taken for O2 to diff.
v2--> Vol of of gas X Diff.
t2-->Time taken for O2 to diff.
There fore 500 * 85500*55 = √Mol. wt of gas XMol. wt of O2 --> ACc to greyham's law...
Now solve to get ans. 289/121 * 32 = 76.42 gm ... Is this the ans.?
