Molarity of a solution of sulphuric acid is 0.8M and its density is 1.06 g/cc. Find the molality and mole fraction of the solution.
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1 Answers
Manish Shankar
·2014-08-01 00:54:24
Lets take the volume as 1 L
so moles of H2SO4=0.8
weight of H2SO4=0.8*98=78.4 g
weight of solution=volume*density=1000*1.06=1060 g
weight of water=1060-78.4=981.6 g
mole of water=981.6/18=54.56
molality=0.8/(0.981.6)
mole fraction=0.8/(0.8+54.56)
- ARKADYUTI BANDYOPADHYAY Thanks,sir!Upvote·0· Reply ·2014-08-04 08:51:56